Search any question & find its solution
Question:
Answered & Verified by Expert
A constant force is applied to a metal wire of length 'L'. Volume of the wire is
constant. The extension produced is proportional to
Options:
constant. The extension produced is proportional to
Solution:
1794 Upvotes
Verified Answer
The correct answer is:
$\mathrm{L}^{2}$
let the volume be $\mathrm{V}$ and area $\mathrm{A}$
$\mathrm{Y}=\frac{\mathrm{Fl}}{\mathrm{A} \Delta \mathrm{l}}$
$\Delta \mathrm{l}=\frac{\mathrm{Fl}}{\mathrm{YA}}$
$V=A \times 1$
$\mathrm{A}=\frac{\mathrm{V}}{\mathrm{l}}$
$\Delta \mathrm{l}=\frac{\mathrm{Fl}^{2}}{\mathrm{YV}}$
$\mathrm{Y}=\frac{\mathrm{Fl}}{\mathrm{A} \Delta \mathrm{l}}$
$\Delta \mathrm{l}=\frac{\mathrm{Fl}}{\mathrm{YA}}$
$V=A \times 1$
$\mathrm{A}=\frac{\mathrm{V}}{\mathrm{l}}$
$\Delta \mathrm{l}=\frac{\mathrm{Fl}^{2}}{\mathrm{YV}}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.