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A constant horizontal force $\overrightarrow{\mathrm{F}}$ of magnitude $10 \mathrm{~N}$ is applied to a block $\mathrm{A}$ and this produces an acceleration of magnitude $20 \mathrm{~m} / \mathrm{s}^2$. If this block $A$ is then kept against another block B of mass $1.5 \mathrm{~kg}$ as shown in figure and a force $\mathrm{F}^{\prime}$ of $20 \mathrm{~N}$ is applied, find the force on the block B. Neglect friction.
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Verified Answer
The correct answer is:
15 N
$\mathrm{m}_{\mathrm{A}}=\frac{10}{20}=0.5 \mathrm{~kg}$
Adding (i) \& (ii), we get
$$
\begin{aligned}
& 20=2 \mathrm{a} \Rightarrow \mathrm{a}=10 \mathrm{~m} / \mathrm{s}^2 \\
& \text { So, } \mathrm{N}=\text { force on } \mathrm{B}=1.5 \mathrm{a}=1.5 \times 10=15 \mathrm{~N}
\end{aligned}
$$
Adding (i) \& (ii), we get
$$
\begin{aligned}
& 20=2 \mathrm{a} \Rightarrow \mathrm{a}=10 \mathrm{~m} / \mathrm{s}^2 \\
& \text { So, } \mathrm{N}=\text { force on } \mathrm{B}=1.5 \mathrm{a}=1.5 \times 10=15 \mathrm{~N}
\end{aligned}
$$
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