Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A constant power \( \mathrm{p} \) is applied to a car starting from rest. If \( \mathrm{v} \) is the velocity of the car at time \( \mathrm{t} \), then
PhysicsWork Power EnergyJEE Main
Options:
  • A \( v \propto t \)
  • B \( v \propto \frac{1}{t} \)
  • C \( v \propto \sqrt{t} \)
  • D \( v \propto \frac{1}{\sqrt{t}} \)
Solution:
1182 Upvotes Verified Answer
The correct answer is: \( v \propto \sqrt{t} \)
Power,
p=m×a×v
p=m×v2t
If p is constant, then for a given body v2t
Or vt

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.