Initial volume, $V_1=47.5$ units
Temperature of ice cold water, $T_1=0 °\mathrm{C}=273\hspace{0.33em}\mathrm{K}$
Final volume, $V_2=67$ units

Applying Charles's law, we have $\frac{V_1}{T_1}=\frac{V_2}{T_2}$ (where temperature $T_2$ is the boiling point)
$\Rightarrow T_2=\frac{V_2}{V_1}\times T_1=\frac{67\times 273}{47.5}=385 \mathrm{K}=112 °\mathrm{C}$