A container is divided into two chambers by a partition. The volume of first chamber is $4.5 \mathrm{litre}$ and second chamber is $5.5 \mathrm{litre}$. The first chamber contain $3.0$ moles of gas at pressure $2.0 \mathrm{atm}$ and second chamber contain $4.0$ moles of gas at pressure $3.0 \mathrm{atm}$. After the partition is removed and the mixture attains equilibrium, then, the common equilibrium pressure existing in the mixture is $x\times {10}^{-1} \mathrm{atm}$. Value of $x$ (nearest integer) is