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A convex lens is dipped in a liquid whose refractive index is equal to refractive index of lens material. Then its focal length will
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The correct answer is:
become infinite
For a lens $\frac{1}{\mathrm{f}}=\left(\mu^{\prime}-1\right)\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right)$
Where $\mu^{\prime}=\frac{\mu_{\mathrm{g}}}{\mu_{\ell}}=1$
$$
\therefore \frac{1}{\mathrm{f}}=0 \text { or } \mathrm{f}=\infty
$$
Where $\mu^{\prime}=\frac{\mu_{\mathrm{g}}}{\mu_{\ell}}=1$
$$
\therefore \frac{1}{\mathrm{f}}=0 \text { or } \mathrm{f}=\infty
$$
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