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A convex mirror has a focal length $f$. A real object is placed at a distance $f$ in front of it from the pole produces an image at
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The correct answer is:
$f$
In case of real object placed in front of convex mirror at a distance \(\mathrm{f}\).
According to sign convention.
Position of object, \(u=-f\)
Focal length, \(\mathrm{f}=+\mathrm{f}\)
Applying mirror formula
\(\begin{aligned}
& \frac{1}{v}+\frac{1}{u}=\frac{1}{f} \\
& =\frac{1}{v}+\frac{1}{(-f)}=\frac{1}{f} \\
& \frac{1}{v}=\frac{2}{f} \\
& \therefore v=\frac{f}{2}
\end{aligned}\)
The positive sign of \(v\) indicates image produced behind the mirror.
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