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A coordinate complex contains $\mathrm{Co}^{3+}, \mathrm{Cl}^{-}$and $\mathrm{NH}_3$. When dissolved in water, one mole of this complex gave a total of 3 moles of ions. The complex is
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Verified Answer
The correct answer is:
$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2$
When the complex dissolved in water, it gives three ions, which shows that two $\mathrm{Cl}^{-}$ions are present outside the coordination sphere.
$\therefore$ The formula of the complex is
$\begin{aligned} & {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2} \\ & {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2 \stackrel{\text { Water }}{\longrightarrow} \underbrace{\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}^{2+}+2 \mathrm{Cl}^{-}\right.}_{3 \text { ion }}}\end{aligned}$
$\therefore$ The formula of the complex is
$\begin{aligned} & {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2} \\ & {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2 \stackrel{\text { Water }}{\longrightarrow} \underbrace{\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}^{2+}+2 \mathrm{Cl}^{-}\right.}_{3 \text { ion }}}\end{aligned}$
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