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Question: Answered & Verified by Expert
A cricket fielder can throw the cricket ball with a speed vo. If he throws the ball while running with speed u at an angle θ to the horizontal, find the effective angle to the horizontal at which the ball is projected in air as seen by a spectator.
ChemistryMotion In Two DimensionsNEET
Options:
  • A $ta{{n}^{-1}}\left( \frac{{{v}_{o}}sin\theta }{{{v}_{o}}sin\theta ~+~u} \right)$
  • B $ta{{n}^{-1}}\left( \frac{{{v}_{o}}cos\theta }{{{v}_{o}}sin\theta ~+~u} \right)$
  • C $ta{{n}^{-1}}\left( \frac{{{v}_{o}}cos\theta }{{{v}_{o}}cos\theta ~+~u} \right)$
  • D $ta{{n}^{-1}}\left( \frac{{{v}_{o}}sin\theta }{{{v}_{o}}cos\theta ~+~u} \right)$
Solution:
2058 Upvotes Verified Answer
The correct answer is: $ta{{n}^{-1}}\left( \frac{{{v}_{o}}sin\theta }{{{v}_{o}}cos\theta ~+~u} \right)$
Correct Option is : (D)
$ta{{n}^{-1}}\left( \frac{{{v}_{o}}sin\theta }{{{v}_{o}}cos\theta ~+~u} \right)$

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