Surface area of cube of edge length 1cm =(6×1)cm².

Surface area of cube of edge length (1×10⁻⁷)cm=(6×10⁻¹⁴)cm²

Let n cubes of 6×10⁻¹⁴cm² are present on dividing the cube of 6cm²

∴n× volume of cube of edge length 10⁻⁷cm=  Volume of cube of edge length 1cm.

$\mathrm{n}\times \left[{10}^{-7}\right]{ }^3=(1{)}^3$

∴n=10²¹

∴ New total surface area =${10}^{21}\times 6\times {10}^{-14}=6\times {10}^7$cm²

Hence, the ratio of total surface area of all the cubes of 1 nmedge length to the surface area of the initial cube is=$\frac{6\times {10}^7}{6}={10}^7$