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A cubic solid is made up of two elements \(P\) and Q. Atoms of \(Q\) are at the corners of the cube and \(P\) at the body centre. What is the formula of the compound? What are the coordination numbers of \(P\) and \(Q\) ?
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As atoms Q are present at the eight corners of the cube, therefore, the contribution of atoms of \(Q\) in the unit cell \(=\frac{1}{8} \times 8=1\).
As atom \(\mathrm{P}\) is present at the body centre, therefore, the contribution of atoms of \(\mathrm{P}\) in the unit cell \(=1\).
\(\therefore\) Ratio of atoms of \(\mathrm{P}: \mathrm{Q}=1: 1\)
Hence, the formula of the compound \(=P Q\)
The coordination number of both \(\mathrm{P}\) and \(\mathrm{Q}=8\).
As atom \(\mathrm{P}\) is present at the body centre, therefore, the contribution of atoms of \(\mathrm{P}\) in the unit cell \(=1\).
\(\therefore\) Ratio of atoms of \(\mathrm{P}: \mathrm{Q}=1: 1\)
Hence, the formula of the compound \(=P Q\)
The coordination number of both \(\mathrm{P}\) and \(\mathrm{Q}=8\).
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