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Question: Answered & Verified by Expert

A current carrying rectangular loop PQRS is made of uniform wire. The length PR=QS=5 cm and PQ=RS=100 cm. If ammeter current reading changes from I to 2I, the ratio of magnetic forces per unit length on the wire PQ due to wire RS in the two cases respectively fPQI:fPQ2I is:

PhysicsMagnetic Effects of CurrentJEE MainJEE Main 2023 (30 Jan Shift 2)
Options:
  • A 1:2
  • B 1:4
  • C 1:5
  • D 1:3
Solution:
1640 Upvotes Verified Answer
The correct answer is: 1:4

Force acting per unit length between two parallel wires is given by, f=μ0I1I22πd.

Clearly, fI1I2

Therefore, fPQI:fPQ2I=I×I2I×2I=1:4

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