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Question: Answered & Verified by Expert
A current I=10sin100πt A is passed in first coil, which induces a maximum EMF of 5π V in second coil. The mutual inductance between the coils is
PhysicsElectromagnetic InductionNEET
Options:
  • A 5 mH
  • B 10 mH
  • C 15 mH
  • D 20 mH
Solution:
1106 Upvotes Verified Answer
The correct answer is: 5 mH
Let current is I=I0 sin ωt,

Where I0 =10, ω=100 π

Then induced e.m.f. is given by

ω=-MdIdt=-MddtI0

ω=-MI0ωcosωt

Maximum e.m.f. is

ω_max=MI0ω

5π = M × 10 × 100π

M = 5 mH

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