A current i is flowing through the loop. The direction of the current and the shape of the loop are as shown in the figure. The magnetic field at the centre of the loop is ( MA = R , MB = 2 R , ∠ DMA = 90 ° )

Question

A current i is flowing through the loop. The direction of the current and the shape of the loop are as shown in the figure. The magnetic field at the centre of the loop is ( MA = R , MB = 2 R , ∠ DMA = 90 ° ), 5 16 μ o i R , but out of the plane of the paper, 5 16 μ 0 i R , but into the plane of the paper, 7 16 μ o i R , but out of the plane of the paper, 7 16 μ o i R , but into the plane of the paper

MARKS App · Accepted Answer

(i) The magnetic field at the centre due to the curved portion DA = μ 0 i 4 π R 3 π 2 According to the right-hand screw rule, the magnetic field will be into the plane of the paper. (ii) The magnetic field at M due to AB is zero. (iii) The magnetic field at the centre due to the curved portion B C is μ 0 i 4 π 2 R π 2 . According to the right-hand screw rule, the magnetic field will be into the plane of the paper. (iv) The magnetic field at M due to DC is zero. Hence, the resultant magnetic field at M B M = B s m a l l l o o p + B b i g l o o p Both are perpendicular downward B M = μ O i 4 π R 3 2 π + μ O i 4 π 2 R π 2 B M = 7 16 μ O i R ⨂

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