Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert

A current of 10.0 A flows for 2.00 h through an electrolytic cell containing a molten salt of metal X. This results in the decomposition of 0.250 mol of metal X at the cathode. The oxidation state of X in the molten salt is:

F=96,500 C

ChemistryElectrochemistryJEE MainJEE Main 2014 (09 Apr Online)
Options:
  • A 1+
  • B 4+
  • C 3+
  • D 2+
Solution:
2266 Upvotes Verified Answer
The correct answer is: 3+

Quantity of Electricity  = 1 0 × 3 6 0 0 × 2 9 6 5 0 0
                                   =0.7460.75F.
If oxidation state is n+ for 1 mol deposition of a metal:
Electricity=nF (Faradays)
For 0.250 mol=0.250 nF
 0.250 nF=0.75 F
n=3

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.