A current of $ 10 A $ passes through two very long wires held parallel to each other and separated by a distance of $ 1 \mathrm{~m} $. The magnitude of force per unit length between them is [Use in $ \frac{\mu_{0}}{4 \pi}=10^{-7} $ S.I. unit]

Question

A current of $ 10 A $ passes through two very long wires held parallel to each other and separated by a distance of $ 1 \mathrm{~m} $. The magnitude of force per unit length between them is [Use in $ \frac{\mu_{0}}{4 \pi}=10^{-7} $ S.I. unit], $ 2 \times 10^{-5} \mathrm{Nm}^{-1} $, $ 3 \times 10^{-5} \mathrm{Nm}^{-1} $, $ 4 \times 10^{-5} \mathrm{Nm}^{-1} $, $ 5 \times 10^{-6} \mathrm{Nm}^{-1} $

MARKS App · Accepted Answer

The magnitude of force per unit length between the two parallel long wires is F l = μ 0 i 2 2 πr = 2 × 10 - 7 10 2 1 = 2 × 10 - 5 N m - 1 .

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