In a moving coil galvanometer, the current is related to the angle of deflection by the formula:

$i\propto \theta ...\left(1\right)$

From equation (1), it follow sthat
$$\begin{gathered} \frac{i_2}{i_1}=\frac{{\theta }_2}{{\theta }_1} \\ \Rightarrow \frac{i_2}{200 \mathrm{\mu A}}=\frac{{\displaystyle \frac{\mathrm{\pi }}{10}}}{{\displaystyle \frac{\mathrm{\pi }}{3}}}=\frac{3}{10} \\ \Rightarrow i_2=60 \mathrm{\mu A} \end{gathered}$$