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A current of $2.5 \mathrm{~A}$ flows through a coil of inductance $5 \mathrm{H}$. The magnetic flux linked with the coil is:
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2274 Upvotes
Verified Answer
The correct answer is:
$12.5 \mathrm{~Wb}$
According to the question
Current $I=2.5 \mathrm{~A}$ and Induction $L=5 \mathrm{H}$
$\therefore$ Magnetic flux linked with coil is
$$
\begin{aligned}
\phi & =L I=(5 \mathrm{H}) \\
(2.5 \mathrm{~A}) & =12.5 \mathrm{~Wb}
\end{aligned}
$$
Current $I=2.5 \mathrm{~A}$ and Induction $L=5 \mathrm{H}$
$\therefore$ Magnetic flux linked with coil is
$$
\begin{aligned}
\phi & =L I=(5 \mathrm{H}) \\
(2.5 \mathrm{~A}) & =12.5 \mathrm{~Wb}
\end{aligned}
$$
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