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A current of $5 \mathrm{~A}$ is passing through a metallic wire of cross-sectional area $4 \times 10^{-6} \mathrm{~m}^{2}$ If the density of charge carriers of the wire is
$5 \times 10^{26} \mathrm{~m}^{-3}$ the drift velocity of the electronswill be
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$5 \times 10^{26} \mathrm{~m}^{-3}$ the drift velocity of the electronswill be
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Verified Answer
The correct answer is:
$1.56 \times 10^{-2} \mathrm{~ms}^{-1}$
Drift velocity, $v_{d}=\frac{1}{n e A}$
$$
\begin{aligned}
\Rightarrow v_{d} &=\frac{5}{\left(5 \times 10^{26}\right) \times\left(1.6 \times 10^{-19}\right) \times\left(4 \times 10^{-6}\right)} \\
&=\frac{1}{64}=1.56 \times 10^{-2} \mathrm{~ms}^{-1}
\end{aligned}
$$
$$
\begin{aligned}
\Rightarrow v_{d} &=\frac{5}{\left(5 \times 10^{26}\right) \times\left(1.6 \times 10^{-19}\right) \times\left(4 \times 10^{-6}\right)} \\
&=\frac{1}{64}=1.56 \times 10^{-2} \mathrm{~ms}^{-1}
\end{aligned}
$$
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