A cyclotron's oscillator frequency is 10 M H z and the radius of its dees is 60 c m , then the kinetic energy of the proton beam produced by the accelerator is [ m proton = 1 . 67 × 10 - 27 kg ]

Question

A cyclotron's oscillator frequency is 10 M H z and the radius of its dees is 60 c m , then the kinetic energy of the proton beam produced by the accelerator is [ m proton = 1 . 67 × 10 - 27 kg ], 9 M e V, 10 M e V, 7 M e V, 11 M e V

MARKS App · Accepted Answer

KE = q 2 B 2 R 2 2 m Given, f = 10 M H z = 10 7 H z R = 60 c m = 0 .6 m f = q B 2 π m ∴ K E = 2 π 2 m f 2 R 2 = 2 × 3 .14 2 × 1.67 × 10 - 27 × 10 14 × 0. 36 J ≈ 7 M e V

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