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A cylinder containing an ideal gas is in vertical position and has a piston of mass $M$ that is able to move up or down without friction (figure). If the temperature is increased
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The correct answer is:
$V$ will change but not $p$
$V$ will change but not $p$
Let us consider the given diagram where an ideal gas is contained in a cylinder, having a piston of mass $M$. The pressure on gas does not change.
The pressure inside the gas will be $p=p_a+M g / A$
where, $p_a=$ atmospheric pressure
$A=$ area of cross-section of the piston.
$M g=$ weight of piston
Hence, $p=$ constant.
As the piston and cylinder is frictionless so the equation for ideal gas
$p V=n R T$, volume $(V)$ increases at constant pressure. as $p, R, n$ are constant so,
$V \propto T$
so on increasing temperature of system its volume increased but $p$ will remain constant.
The pressure inside the gas will be $p=p_a+M g / A$
where, $p_a=$ atmospheric pressure
$A=$ area of cross-section of the piston.
$M g=$ weight of piston
Hence, $p=$ constant.
As the piston and cylinder is frictionless so the equation for ideal gas
$p V=n R T$, volume $(V)$ increases at constant pressure. as $p, R, n$ are constant so,
$V \propto T$
so on increasing temperature of system its volume increased but $p$ will remain constant.
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