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A cylinder of height his filled with wator and is kept on a block of height $h / 2$ The level of water in the cylinder is kept constant. Four holes numbered 1,2,3 and 4 are at the side of the cylinder and at heights $0, h / 4, h / 2$ and $3 h / 4,$ respectively. When all four holes are openned together, the hole from which water will reach farthest distance on the plane $P Q$ is the hole number.
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The correct answer is:
2
Height of the cylinder from the level $P O$ is $H=h+\frac{h}{2}=\frac{3 h}{2}$
To cover maximum distance along the plane $P Q$, height of the hole is $=\frac{3 h}{2} \times \frac{1}{2}=\frac{3 h}{4}$
This height corresponds to hole (2).
To cover maximum distance along the plane $P Q$, height of the hole is $=\frac{3 h}{2} \times \frac{1}{2}=\frac{3 h}{4}$
This height corresponds to hole (2).
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