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Question: Answered & Verified by Expert
A cylindrical conductor of diameter 0.1mcarries a current of 90 mA. The current density (in m-2 ) is π3
PhysicsCurrent ElectricityNEET
Options:
  • A 1.2×107
  • B 3×106
  • C 6×106
  • D 2.4×107
Solution:
2838 Upvotes Verified Answer
The correct answer is: 1.2×107
Given,

The diameter of the cylindrical conductor D=0.01 mm

Radius r=D2=0.12  mm

Current I=90 mA=90×10-3A

We know that,

Current density J=IA

=Iπr2

=90×10-3227×0.1×10-3 22

=90×10-3 3.14×0.1×10-3 22

=12000×103

=1.2×107 A m-2

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