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A cylindrical container containing water has a small hole at height of \( \mathrm{H}=8 \mathrm{~cm} \) from the bottom
and at a depth of \( 2 \mathrm{~cm} \) from the top surface of the liquid. The maximum horizontal distance
travelled by the water before it hits the ground \( (x) \) is
Options:
and at a depth of \( 2 \mathrm{~cm} \) from the top surface of the liquid. The maximum horizontal distance
travelled by the water before it hits the ground \( (x) \) is
Solution:
1896 Upvotes
Verified Answer
The correct answer is:
\( 8 \mathrm{~cm} \)
(B)
\[
\begin{array}{l}
v=\sqrt{2 g h}=\sqrt{2 \times 10 \times 2}=\sqrt{40} \\
t=\sqrt{\frac{2 h}{g}} \\
R=v \cdot t=\sqrt{40^{4}} \sqrt{\frac{2 \times 8}{10}}=8 \mathrm{~cm}
\end{array}
\]
\[
\begin{array}{l}
v=\sqrt{2 g h}=\sqrt{2 \times 10 \times 2}=\sqrt{40} \\
t=\sqrt{\frac{2 h}{g}} \\
R=v \cdot t=\sqrt{40^{4}} \sqrt{\frac{2 \times 8}{10}}=8 \mathrm{~cm}
\end{array}
\]
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