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A cylindrical furnace has height H and diameter D both 1 m. It is maintained at temperature 360 K. The air gets heated inside the furnace at constant pressure Pa and its temperature becomes T=360 K. The hot air with density ρ rises up a vertical chimney of diameter d=0.1 m and height h=9 m above the furnace and exits the chimney (see the figure). As a result, atmospheric air of density ρa=1.2 kg m-3, pressure Pa and temperature Ta=300 K enters the furnace. Assume air as an ideal gas, neglect the variations in ρ and T inside the chimney and the furnace. Also ignore the viscous effects.



[Given: The acceleration due to gravity g=10 m s-2 and π=3.14]





When the chimney is closed using a cap at the top, a pressure difference P develops between the top and the bottom surfaces of the cap. If the changes in the temperature and density of the hot air, due to the stoppage of air flow, are negligible then the value of P is _____ N m2.
PhysicsMechanical Properties of FluidsJEE AdvancedJEE Advanced 2023 (Paper 2)
Solution:
1232 Upvotes Verified Answer
The correct answer is: 7850

Applying Bernoulli’s theorem between top and bottom points of furnace :

Pa+12ρaV2=Pa+ρgH+12ρV2                ... 1

Also, since PM=ρRT

 ρa×300=ρ×360

 ρ=1 kg m-3             ... 2

From equation(1), we can write

 V220.2=1×10×1

 V=10 m s-1

Now, let V' be the speed of air in chimney.

 By continuity equation,

πD24·V=πd24·V'

 V'=100V=1000 m s-1

Therefore, pressure difference p

=ρV'2·area

=1×10002×πd24=1×10002×3.14×0.124=7850 N m2

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