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A cylindrical tube open at both ends has a fundamental
frequency 'f' in air. The tube is dipped vertically in water so
that half of it is in water. The new fundamental frequency is
Options:
frequency 'f' in air. The tube is dipped vertically in water so
that half of it is in water. The new fundamental frequency is
Solution:
1176 Upvotes
Verified Answer
The correct answer is:
f
Initially
$$
\mathrm{f}=\frac{\mathrm{V}}{2 \ell}
$$
Finally
From diagram, we can see
$$
\begin{aligned}
& \frac{\lambda}{4}=\frac{\ell}{2} \\
& \Rightarrow \lambda=21
\end{aligned}
$$
Now, fundamental frequency
$$
=\frac{\mathrm{V}}{\lambda}=\frac{\mathrm{V}}{2 \ell}=\mathrm{f}
$$
So, there will be no change in fundamental frequency.
$$
\mathrm{f}=\frac{\mathrm{V}}{2 \ell}
$$
Finally
From diagram, we can see
$$
\begin{aligned}
& \frac{\lambda}{4}=\frac{\ell}{2} \\
& \Rightarrow \lambda=21
\end{aligned}
$$
Now, fundamental frequency
$$
=\frac{\mathrm{V}}{\lambda}=\frac{\mathrm{V}}{2 \ell}=\mathrm{f}
$$
So, there will be no change in fundamental frequency.
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