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A decapeptide (molecular weight 796) on complete hydrolysis gives glycine (molecular weight 75), alanine and phenylalanine. Glycine contributes $47.0 \%$ to the total weight of the hydrolysed products. The number of glycine units present in the decapeptide is
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The correct answer is:
6
$$
\text { A decapeptide has nine peptide (amide) linkage as }
$$
Therefore, no hydrolysis, it will absorb nine water molecules.
Hence, total mass of hydrolysis product $=796+18 \times 9=958$
$\Rightarrow$ mass of glycine in hydrolysis product $=\frac{958 \times 47}{100}=450$
$\Rightarrow$ number of glycine molecule in one molecule of decapeptide $=\frac{450}{75}=6$
\text { A decapeptide has nine peptide (amide) linkage as }
$$
Therefore, no hydrolysis, it will absorb nine water molecules.
Hence, total mass of hydrolysis product $=796+18 \times 9=958$
$\Rightarrow$ mass of glycine in hydrolysis product $=\frac{958 \times 47}{100}=450$
$\Rightarrow$ number of glycine molecule in one molecule of decapeptide $=\frac{450}{75}=6$
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