Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A diatomic ideal gas undergoes a thermodynamic change according to the P-V diagram shown in the figure. The total heat given to the gas is nearly (use ln2=0.7 )

PhysicsThermodynamicsNEET
Options:
  • A 2.5P0V0
  • B 1.4P0V0
  • C 39P0V0
  • D 1.1P0V0
Solution:
1327 Upvotes Verified Answer
The correct answer is: 39P0V0
QAB=ΔUAB+WAB,  where  WAB=0

ΔUAB=f2nRΔT

ΔUAB=f2ΔPV

ΔUAB=52ΔPV

ΔUAB=2.5ΔPV

According to the first law of thermodynamics QAB=ΔUAB+WAB

Where WAB=0

therefore QAB=ΔUAB

QAB=2.5P0V0



Process BC

QBC=ΔUBC+WBC

   QBC=0+2P0V0ln2

QBC=1.4P0V0

Qnet=QAB+QBC=3.9P0V0

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.