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A dice is thrown ten times. If getting even number is considered as a success, then the probability of four successes is
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Verified Answer
The correct answer is:
${ }^{10} C_6\left(\frac{1}{2}\right)^{10}$
Required probability
$={ }^{10} C_4\left(\frac{1}{2}\right)^4\left(\frac{1}{2}\right)^6$ $={ }^{10} C_4\left(\frac{1}{2}\right)^{10}={ }^{10} C_6\left(\frac{1}{2}\right)^{10}$.
$={ }^{10} C_4\left(\frac{1}{2}\right)^4\left(\frac{1}{2}\right)^6$ $={ }^{10} C_4\left(\frac{1}{2}\right)^{10}={ }^{10} C_6\left(\frac{1}{2}\right)^{10}$.
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