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A die is thrown 10 times, the probability that an odd number will come up at least one time is
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$\frac{1023}{1024}$
A die is thrown 10 times Probability of success is an odd number $\therefore \quad n=10, p=\frac{1}{2}, q=\frac{1}{2}$
Number of success is atleast one Required probability $P(x \geq 1)=1-P(x=0)$
$=1-{ }^{10} C_{0}\left(\frac{1}{2}\right)^{0}\left(\frac{1}{2}\right)^{10}$
$=1-\frac{1}{1024}=\frac{1023}{1024}$
Number of success is atleast one Required probability $P(x \geq 1)=1-P(x=0)$
$=1-{ }^{10} C_{0}\left(\frac{1}{2}\right)^{0}\left(\frac{1}{2}\right)^{10}$
$=1-\frac{1}{1024}=\frac{1023}{1024}$
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