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A die is tossed thrice. If getting a four is considered a success, then the mean and variance of the probability distribution of the number of successes are
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We are given that $n=3, \quad p=\frac{1}{6}, \quad q=\frac{5}{6}$
Mean $=n p=3 \times \frac{1}{6}=\frac{1}{2}$
Variance $=n q p=3 \times \frac{1}{6} \times \frac{5}{6}=\frac{5}{12}$.
Mean $=n p=3 \times \frac{1}{6}=\frac{1}{2}$
Variance $=n q p=3 \times \frac{1}{6} \times \frac{5}{6}=\frac{5}{12}$.
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