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A difference of $2.3 \mathrm{eV}$ separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
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Verified Answer
Given $E_f-E_i=2.3 \mathrm{eV}$
Also, hv $=\mathrm{E}_{\mathrm{f}}-\mathrm{E}_{\mathrm{i}}=2.3 \mathrm{eV}=2.3 \times 1.6 \times 10^{-19} \mathrm{~J}$
$$
\begin{aligned}
\Rightarrow \quad v &=\frac{2.3 \times 1.6 \times 10^{-19}}{\mathrm{~h}}=\frac{2.3 \times 1.6 \times 10^{-19}}{6.6 \times 10^{-34}} \\
&=0.557 \times 10^{15} \simeq 5.6 \times 10^{14} \mathrm{~Hz}
\end{aligned}
$$
Also, hv $=\mathrm{E}_{\mathrm{f}}-\mathrm{E}_{\mathrm{i}}=2.3 \mathrm{eV}=2.3 \times 1.6 \times 10^{-19} \mathrm{~J}$
$$
\begin{aligned}
\Rightarrow \quad v &=\frac{2.3 \times 1.6 \times 10^{-19}}{\mathrm{~h}}=\frac{2.3 \times 1.6 \times 10^{-19}}{6.6 \times 10^{-34}} \\
&=0.557 \times 10^{15} \simeq 5.6 \times 10^{14} \mathrm{~Hz}
\end{aligned}
$$
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