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A dihaloalkane ' $X$, having formula $\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{Cl}_{2}$, on hydrolysis gives a compound, that can reduce Tollen's reagent. The compound $X^{\prime}$ is
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1 , 1 -dichloropropane
Since, the obtained compound reduces Tollen's reagent, it must be an aldehyde. Thus, it is obvious that both the $-\mathrm{Cl}$ atoms are present at $\mathrm{C}_{1} . \quad$ Hence, $\quad$ the $\quad$ compound $\quad{X}^{\prime}$ is 1, 1-dichloropropane and the reactions are as follows
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