A dip needle vibrates in the vertical plane perpendicular to the magnetic meridian. The time period of vibration is found to be 2 s . The same needle is then allowed to vibrate in the horizontal plane, and the time period is again found to be 2 s . Then the angle of dip is

Question

A dip needle vibrates in the vertical plane perpendicular to the magnetic meridian. The time period of vibration is found to be 2 s . The same needle is then allowed to vibrate in the horizontal plane, and the time period is again found to be 2 s . Then the angle of dip is, 0 °, 30 °, 45 °, 90 °

MARKS App · Accepted Answer

Time period when dip needle vibrates in the vertical plane perpendicular to the magnetic meridian is, T 1 = 2 π I M B V The time period of vibration when needle is allowed to vibrate in the horizontal plane is, T 2 = 2 π I M B H as T 1 = T 2 = 2 s ∴ B V = B H Angle of dip is, tan ⁡ θ = B v B H = 1 θ = 45 °

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