A disc of mass $ M $ and radius $ R $ is rolling with angular speed $ \omega $ on a horizontal plane as shown. The magnitude of angular momentum of the disc about the origin $ O $ is

Question

A disc of mass $ M $ and radius $ R $ is rolling with angular speed $ \omega $ on a horizontal plane as shown. The magnitude of angular momentum of the disc about the origin $ O $ is, $ \left(\frac{1}{2}\right) M R^{2} \omega $, $ M R^{2} \omega $, $ \left(\frac{3}{2}\right) M R^{2} \omega $, $ 2 M R^{2} \omega $

MARKS App · Accepted Answer

From the theorem L → = L cm → + M ( r → × v → ) Angular momentum about O = Angular momentum about CM + Angular momentum of CM about origin L 0 = I ω + MR v = M R 2 ω 2 + M R 2 ω = ( 3 2 ) M R 2 ω

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