Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A disc of radius $2 \mathrm{~m}$ is rotating with angular is to be put on the disc. Friction coefficient between disc and block is $\mu_{\mathrm{K}}=0.3$, then find the maximum distance from axis where the block can be placed without sliding
PhysicsMotion In Two DimensionsAIIMSAIIMS 2019 (26 May)
Options:
  • A $2 \mathrm{~cm}$
  • B $3 \mathrm{~cm}$
  • C $4 \mathrm{~cm}$
  • D $6 \mathrm{~cm}$
Solution:
1605 Upvotes Verified Answer
The correct answer is: $3 \mathrm{~cm}$
$\begin{aligned} & \text { Friction force }=\text { centripetal force } \mu_{\mathrm{K}}(m g) \\ & =m \omega^2 x \\ & \mu_{\mathrm{K}} \cdot g=\omega^2 x \\ & 0.3 \times 10=(10)^2 x \Rightarrow x=\frac{3}{100} \mathrm{~m}=3 \mathrm{~cm}\end{aligned}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.