Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A disc of radius R and mass M is pivoted at the rim and is set for small oscillations. If simple pendulum has to have the same period as that of the disc, the length of the simple pendulum should be
PhysicsOscillationsJEE Main
Options:
  • A 54R
  • B 23R
  • C 34R
  • D 32R
Solution:
2441 Upvotes Verified Answer
The correct answer is: 32R


τ=-mgRsinθ=-mgRθ   sinθθ

Iα =12mR2+mR2α=32mR2α

But τ= Iα

32mR2α=-mgRθ

α=-2g3Rθ=ω2θ

Time period T=2π3R2g

For simple pendulum, T=2πlg

l=3R2

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.