A diver at a depth of $12 \mathrm{~m}$ in water $\left(\mu=\frac{4}{3}\right)$ sees the sky in a cone of semivertical angle :

Question

A diver at a depth of $12 \mathrm{~m}$ in water $\left(\mu=\frac{4}{3}\right)$ sees the sky in a cone of semivertical angle :, $\sin ^{-1}\left(\frac{4}{3}\right)$, $\tan ^{-1}\left(\frac{4}{3}\right)$, $\sin ^{-1}\left(\frac{3}{4}\right)$, $90^{\circ}$

MARKS App · Accepted Answer

Hints: $c=\sin ^{-1}\left(\frac{1}{\mu}\right)$ $=\sin ^{-1}\left(\frac{3}{4}\right)$

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