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A Diwali cracker releases 25 gram gas per second, with a speed of $400 \mathrm{~ms}^{-1}$ after
explosion. The force exerted by gas on the cracker is
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explosion. The force exerted by gas on the cracker is
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The correct answer is:
10 newton
$\mathrm{F}=$ rate of change of momentum
$=25 \times 10^{-3} \mathrm{~kg} / \mathrm{s} \times 400 \mathrm{~m} / \mathrm{s}$ $=10 \mathrm{~N}$
$=25 \times 10^{-3} \mathrm{~kg} / \mathrm{s} \times 400 \mathrm{~m} / \mathrm{s}$ $=10 \mathrm{~N}$
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