A double-slit experiment is immersed in a liquid of refractive index 1.33 . The separation between the slits is 1 mm and the distance between the slit and screen is 1.33 m . If slits are illuminated by a parallel beam of light whose wavelength is 6300 A ∘ , then fringe width will be

Question

A double-slit experiment is immersed in a liquid of refractive index 1.33 . The separation between the slits is 1 mm and the distance between the slit and screen is 1.33 m . If slits are illuminated by a parallel beam of light whose wavelength is 6300 A ∘ , then fringe width will be, 6.3 mm, 63 mm, 0.63 mm, None of these

MARKS App · Accepted Answer

Given, λ = 6300 Å = 6300 × 10 - 10 m = 6.3 × 10 - 7 m When equipment is immersed in a liquid of refractive index 1.33, then wavelength λ is changed. ∴ λ ′ = λ μ = 6.3 × 10 - 7 1.33 ∴ Fringe width, β = D λ ′ d = 1.33 × 6.3 × 10 - 7 1 × 10 - 3 × 1.33 = 6.3 × 10 - 4 = 0.63 × 10 - 3 m = 0.63 mm

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