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A factory produces $40 \mathrm{~kg}$ of calcium in two hours by electrolysis. How much aluminium can be produced by same current in 2 hours if current efficiency is $50 \%$ ?
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$9 \mathrm{~kg}$
$\frac{W_{\mathrm{Ca}}}{E_{\mathrm{Ca}}}=\frac{W_{\mathrm{Al}}}{E_{\mathrm{Al}}} \Rightarrow \frac{40}{20}=\frac{W_{\mathrm{Al}}}{9} \Rightarrow W_{\mathrm{Al}}=18 \mathrm{~kg}$
As current efficiency is $50 \% \mathrm{so}, W_{\mathrm{Al}}=9 \mathrm{~kg}$
As current efficiency is $50 \% \mathrm{so}, W_{\mathrm{Al}}=9 \mathrm{~kg}$
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