Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A fair coin is tossed 2 times. A person receives $₹ X^{3}$ if he gets $X$ number of heads.
His expected gain is $=$
MathematicsProbabilityMHT CETMHT CET 2020 (15 Oct Shift 1)
Options:
  • A $₹ 2.00$
  • B $₹ 1.00$
  • C $₹ 2.50$
  • D $₹ 5.20$
Solution:
1175 Upvotes Verified Answer
The correct answer is: $₹ 2.50$
A fair coin is tossed 2 times. Possible outcomes are HH, HT, TH, TT $\therefore X$ takes values $0,1,2$
$$
\therefore P(X=0)=\frac{1}{4}, P(X=1)=\frac{2}{4}=\frac{1}{2}, P(X=2)=\frac{1}{4}
$$
Given a person receives $₹ X^{3}$ if we gets $X$ no. of heads.
$$
\begin{aligned}
\therefore \text { Expected gain } &=\left(\frac{1}{4} \times 0\right)+\left(\frac{1}{2} \times 1^{3}\right)+\left(\frac{1}{4} \times 2^{3}\right) \\
&=0+\frac{1}{2}+\frac{8}{4}=2.5
\end{aligned}
$$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.