Search any question & find its solution
Question:
Answered & Verified by Expert
A fair coin is tossed repeatedly. The probability of getting a result in the fifth toss different from those obtained in the first four tosses is:
Options:
Solution:
1173 Upvotes
Verified Answer
The correct answer is:
$\frac{1}{16}$
P(HHHHT or TTTTH) = P (HHHHT) + P (TTTTH)
$=\left(\frac{1}{2}\right)^{5}+\left(\frac{1}{2}\right)^{5}=\frac{1}{16}$
$=\left(\frac{1}{2}\right)^{5}+\left(\frac{1}{2}\right)^{5}=\frac{1}{16}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.