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A fair die is tossed twice in succession. If $X$ denotes the number of sixes in two tosses, then the probability distribution of $X$ is given by
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The correct answer is:

$P($ zero sin $)=\frac{25}{36}, P($ one sin $)=\frac{10}{36}, P($ two sixes $)=\frac{1}{36}$
Hence probability distribution

Hence probability distribution

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