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A fan is making 600 revolutions per minute. If after some time it makes 1200 revolutions per minute, then increase in its angular velocity
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Verified Answer
The correct answer is:
$20 \pi \mathrm{rad} / \mathrm{sec}$
$20 \pi \mathrm{rad} / \mathrm{sec}$
$\omega=600 \times \frac{2 \pi}{60}=20 \pi \mathrm{rad} / \mathrm{s}$
$\omega$ is doubled if it takes $1200 \mathrm{rpm}$
$\omega_0=\frac{1200 \times 2 \pi}{60}=40 \pi \mathrm{rad} / \mathrm{s}$
$\therefore \Delta \omega=\omega_0-\omega=20 \pi \mathrm{rad} / \mathrm{s}$
$\omega=600 \times \frac{2 \pi}{60}=20 \pi \mathrm{rad} / \mathrm{s}$
$\omega$ is doubled if it takes $1200 \mathrm{rpm}$
$\omega_0=\frac{1200 \times 2 \pi}{60}=40 \pi \mathrm{rad} / \mathrm{s}$
$\therefore \Delta \omega=\omega_0-\omega=20 \pi \mathrm{rad} / \mathrm{s}$
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