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Question: Answered & Verified by Expert
A far sighted person has his near point $50 \mathrm{~cm}$, find the power of lens he should use to see at $25 \mathrm{~cm}$, clearly.
PhysicsRay OpticsAIIMSAIIMS 2011
Options:
  • A $+1 \mathrm{D}$
  • B $+2 \mathrm{D}$
  • C $-2 \mathrm{D}$
  • D $-1 \mathrm{D}$
Solution:
1649 Upvotes Verified Answer
The correct answer is: $+2 \mathrm{D}$
Here $u=-25 \mathrm{~cm}, v=-50 \mathrm{~cm}$
We have $\frac{1}{f}=\frac{1}{-u}+\frac{1}{v}$
i.e, $\frac{1}{f}=\frac{1}{25}-\frac{1}{50} \quad$ or $f=50 \mathrm{~cm}$
Power of lens he should use,
$$
P=\frac{100}{f}=\frac{100}{50}=+2 \mathrm{D}
$$

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