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Question: Answered & Verified by Expert
A fighter plane, flying horizontally with a speed \( 360 \mathrm{~km} / \mathrm{h} \) at an altitude of \( 500 \mathrm{~m} \) drops a bomb for a target straight ahead of it on the ground. The bomb should be dropped at what approximate distance ahead of the target? Assume that acceleration due to gravity \( (g) \) is \( 10 \mathrm{~ms}^{-2} \). Also, neglect air drag.
PhysicsMotion In Two DimensionsJEE Main
Options:
  • A \( 1000 \mathrm{~m} \)
  • B \( 50 \sqrt{5} \mathrm{~m} \)
  • C \( 500 \sqrt{5} \mathrm{~m} \)
  • D \( 866 \mathrm{~m} \)
Solution:
1284 Upvotes Verified Answer
The correct answer is: \( 1000 \mathrm{~m} \)

Given, speed of fighter plane, v=360 km/h

=360×518 m/s=100 m/s

Altitude, h=500 m

Now, from equation of motion,
h=ut+12gt2

  500=0t+12×10×t2  u=0 and g=10 m/s2

  t2=100t=10 s
The bomb should be dropped at the distance,
x=vt=100×10=1000 m

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