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A fish in water (refractive index $n$ ) looks at a bird vertically above in the air. If $y$ is the height of the bird and $x$ is the depth of the fish from the surface, then the distance of the bird as estimated by the fish is
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The correct answer is:
$x+n y$
When object is in rarer medium and observer is in denser medium, then normal shift,
$d=(n-1) h$
where, $h=$ real depth $=y$
Now, apparent depth or the apparent height of the bird from the surface of the water $=y+(n-1) y=n y$. The total distance of the bird as estimated by fish is $x+n y$.
$d=(n-1) h$
where, $h=$ real depth $=y$
Now, apparent depth or the apparent height of the bird from the surface of the water $=y+(n-1) y=n y$. The total distance of the bird as estimated by fish is $x+n y$.
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