Search any question & find its solution
Question:
Answered & Verified by Expert
A fish looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is $4 / 3$ and the fish is $12 \mathrm{~cm}$ below the surface, the radius of this circle (in $\mathrm{cm}$ ) is
Options:
Solution:
2439 Upvotes
Verified Answer
The correct answer is:
$36 / \sqrt{7}$
$\sin i_{c}=\frac{1}{\mu}=\frac{r}{\sqrt{r^{2}+h^{2}}}$
Using $h=12 \mathrm{~cm}, \mu=4 / 3$
We get $\mathrm{r}=\frac{36}{\sqrt{7}} \mathrm{~cm}$
Using $h=12 \mathrm{~cm}, \mu=4 / 3$
We get $\mathrm{r}=\frac{36}{\sqrt{7}} \mathrm{~cm}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.