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A fish looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is $4 / 3$ and the fish is $12 \mathrm{~cm}$ below the surface, the radius of this circle in $\mathrm{cm}$ is
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The correct answer is:
$36 / \sqrt{7}$
$36 / \sqrt{7}$
$r=\frac{h}{\sqrt{\mu^2-1}}=\frac{36}{\sqrt{7}}$
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